MACD公式中出现底背离时的选股公式-同花顺答疑

	编写条件： 编写方法： 网友求助： DIFF : EMA(CLOSE,SHORT) - EMA(CLOSE,LONG); DEA : EMA(DIFF,M); macd=2*(DIFF-DEA); Zero : 0; gj:=MAX(C,O); STICKLINE(MacD>0 AND MACD>=REF(MACD,1),0,MACD,2,0),color0000ff; STICKLINE(MACD>0 AND MACD<REF(MACD,1),0,MACD,2,0),colorffff00; STICKLINE(MACD<0 AND MACD>=REF(MACD,1),0,MACD,2,0),colorff00ff; STICKLINE(MACD<0 AND MACD<REF(MACD,1),0,MACD,2,0),color00ff00; L4:=LLV(gj,4); jl:=(HHV(diff,55)-LLV(diff,55))/5; gt:=dea>REF(dea,1) AND REF(dea,1)<REF(dea,2); A1:=BArslAST(REF(gt,1)); 底背离:=REF(L4,A1+1)>CLOSE AND diff>REF(diff,A1+1) AND gt; DRAWLINE(A1=0,DEA,底背离,REF(DEA,A1),0),colorred,LINETHICK2; DRAWLINE(底背离,DEA,底背离,REF(DEA,A1),0),colorred,LINETHICK2; DRAWTEXT(底背离,REF(DEA,A1)*1.18,' 底背离'),COLORFF00FF; H4:=HHV(gj,4); gt2:=dea<REF(dea,1) AND REF(dea,1)>REF(dea,2); A2:=BARSLAST(REF(gt2,1)); 顶背离:= REF(H4,A2+1)<H4 AND diff<REF(diff,A2+1) AND gt2; DRAWLINE(A2=0 ,DEA,顶背离,REF(DEA,A2),0),colorgreen,LINETHICK2; DRAWLINE(顶背离,DEA,顶背离,REF(DEA,A2),0),colorgreen,LINETHICK2; DRAWTEXT(顶背离,REF(DEA,A2)*1.18,' 顶背离'),colorgreen; 解答如下： DIFF:=EMA(CLOSE,12) - EMA(CLOSE,26); DEA:=EMA(DIFF,9); GT:=DEA>REF(DEA,1) AND REF(DEA,1)<REF(DEA,2); A1:=BARSLAST(REF(GT,1)); GJ:=MAX(C,O); L4:=LLV(GJ,4); 底背离:REF(L4,A1+1)>CLOSE AND DIFF>REF(DIFF,A1+1) AND GT;