简单公式 求改成大智慧L2能用的-大智慧答疑

	编写条件： 编写方法： 网友求助： 抄底: PSY.psy<=25,STICK,COLORYELLOW,LINETHICK2; STICKLINE(crOSS(PSY.PSY,30),0,1,2,0); WZ1:=MA(CLOSE,5); WZ2:=MA(CLOSE,10); WZ3:=MA(CLOSE,20); WZ5:=MA(CLOSE,60); JD5:ATAN((WZ1/REF(WZ1,1)-1)*100)*57.3,NODRAW; JD10:ATAN((WZ2/REF(WZ2,1)-1)*100)*57.3,NODRAW; JD20:ATAN((WZ3/REF(WZ3,1)-1)*100)*57.3,NODRAW; JD60:ATAN((WZ5/REF(WZ5,1)-1)*100)*57.3,NODRAW; 解答如下： PSY:COUNT(CLOSE>REF(CLOSE,1),12)/12*100,LINETHICK0; 抄底: PSY<=25,STICK,COLORYELLOW,LINETHICK2; STICKLINE(CROSS(PSY,30),0,1,8,0),COLOR00FFFF; WZ1:=MA(CLOSE,5); WZ2:=MA(CLOSE,10); WZ3:=MA(CLOSE,20); WZ5:=MA(CLOSE,60); JD5:ATAN((WZ1/REF(WZ1,1)-1)*100)*57.3,LINETHICK0; JD10:ATAN((WZ2/REF(WZ2,1)-1)*100)*57.3,LINETHICK0; JD20:ATAN((WZ3/REF(WZ3,1)-1)*100)*57.3,LINETHICK0; JD60:ATAN((WZ5/REF(WZ5,1)-1)*100)*57.3,LINETHICK0; CROSS(JD60,10) AND JD10>20,LINETHICK2,COLORWHITE;